3.2269 \(\int \frac{\left (a+b x+c x^2\right )^2}{(d+e x)^{5/2}} \, dx\)

Optimal. Leaf size=162 \[ \frac{2 \sqrt{d+e x} \left (-2 c e (3 b d-a e)+b^2 e^2+6 c^2 d^2\right )}{e^5}+\frac{4 (2 c d-b e) \left (a e^2-b d e+c d^2\right )}{e^5 \sqrt{d+e x}}-\frac{2 \left (a e^2-b d e+c d^2\right )^2}{3 e^5 (d+e x)^{3/2}}-\frac{4 c (d+e x)^{3/2} (2 c d-b e)}{3 e^5}+\frac{2 c^2 (d+e x)^{5/2}}{5 e^5} \]

[Out]

(-2*(c*d^2 - b*d*e + a*e^2)^2)/(3*e^5*(d + e*x)^(3/2)) + (4*(2*c*d - b*e)*(c*d^2
- b*d*e + a*e^2))/(e^5*Sqrt[d + e*x]) + (2*(6*c^2*d^2 + b^2*e^2 - 2*c*e*(3*b*d
- a*e))*Sqrt[d + e*x])/e^5 - (4*c*(2*c*d - b*e)*(d + e*x)^(3/2))/(3*e^5) + (2*c^
2*(d + e*x)^(5/2))/(5*e^5)

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Rubi [A]  time = 0.195023, antiderivative size = 162, normalized size of antiderivative = 1., number of steps used = 2, number of rules used = 1, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.045 \[ \frac{2 \sqrt{d+e x} \left (-2 c e (3 b d-a e)+b^2 e^2+6 c^2 d^2\right )}{e^5}+\frac{4 (2 c d-b e) \left (a e^2-b d e+c d^2\right )}{e^5 \sqrt{d+e x}}-\frac{2 \left (a e^2-b d e+c d^2\right )^2}{3 e^5 (d+e x)^{3/2}}-\frac{4 c (d+e x)^{3/2} (2 c d-b e)}{3 e^5}+\frac{2 c^2 (d+e x)^{5/2}}{5 e^5} \]

Antiderivative was successfully verified.

[In]  Int[(a + b*x + c*x^2)^2/(d + e*x)^(5/2),x]

[Out]

(-2*(c*d^2 - b*d*e + a*e^2)^2)/(3*e^5*(d + e*x)^(3/2)) + (4*(2*c*d - b*e)*(c*d^2
- b*d*e + a*e^2))/(e^5*Sqrt[d + e*x]) + (2*(6*c^2*d^2 + b^2*e^2 - 2*c*e*(3*b*d
- a*e))*Sqrt[d + e*x])/e^5 - (4*c*(2*c*d - b*e)*(d + e*x)^(3/2))/(3*e^5) + (2*c^
2*(d + e*x)^(5/2))/(5*e^5)

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Rubi in Sympy [A]  time = 40.3035, size = 158, normalized size = 0.98 \[ \frac{2 c^{2} \left (d + e x\right )^{\frac{5}{2}}}{5 e^{5}} + \frac{4 c \left (d + e x\right )^{\frac{3}{2}} \left (b e - 2 c d\right )}{3 e^{5}} + \frac{2 \sqrt{d + e x} \left (2 a c e^{2} + b^{2} e^{2} - 6 b c d e + 6 c^{2} d^{2}\right )}{e^{5}} - \frac{4 \left (b e - 2 c d\right ) \left (a e^{2} - b d e + c d^{2}\right )}{e^{5} \sqrt{d + e x}} - \frac{2 \left (a e^{2} - b d e + c d^{2}\right )^{2}}{3 e^{5} \left (d + e x\right )^{\frac{3}{2}}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  rubi_integrate((c*x**2+b*x+a)**2/(e*x+d)**(5/2),x)

[Out]

2*c**2*(d + e*x)**(5/2)/(5*e**5) + 4*c*(d + e*x)**(3/2)*(b*e - 2*c*d)/(3*e**5) +
2*sqrt(d + e*x)*(2*a*c*e**2 + b**2*e**2 - 6*b*c*d*e + 6*c**2*d**2)/e**5 - 4*(b*
e - 2*c*d)*(a*e**2 - b*d*e + c*d**2)/(e**5*sqrt(d + e*x)) - 2*(a*e**2 - b*d*e +
c*d**2)**2/(3*e**5*(d + e*x)**(3/2))

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Mathematica [A]  time = 0.252958, size = 132, normalized size = 0.81 \[ \frac{2 \sqrt{d+e x} \left (\frac{30 (2 c d-b e) \left (e (a e-b d)+c d^2\right )}{d+e x}-\frac{5 \left (e (a e-b d)+c d^2\right )^2}{(d+e x)^2}+30 a c e^2+15 b^2 e^2+2 c e x (5 b e-7 c d)-80 b c d e+73 c^2 d^2+3 c^2 e^2 x^2\right )}{15 e^5} \]

Antiderivative was successfully verified.

[In]  Integrate[(a + b*x + c*x^2)^2/(d + e*x)^(5/2),x]

[Out]

(2*Sqrt[d + e*x]*(73*c^2*d^2 - 80*b*c*d*e + 15*b^2*e^2 + 30*a*c*e^2 + 2*c*e*(-7*
c*d + 5*b*e)*x + 3*c^2*e^2*x^2 - (5*(c*d^2 + e*(-(b*d) + a*e))^2)/(d + e*x)^2 +
(30*(2*c*d - b*e)*(c*d^2 + e*(-(b*d) + a*e)))/(d + e*x)))/(15*e^5)

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Maple [A]  time = 0.01, size = 194, normalized size = 1.2 \[ -{\frac{-6\,{x}^{4}{c}^{2}{e}^{4}-20\,bc{e}^{4}{x}^{3}+16\,{x}^{3}{c}^{2}d{e}^{3}-60\,{x}^{2}ac{e}^{4}-30\,{b}^{2}{e}^{4}{x}^{2}+120\,bcd{e}^{3}{x}^{2}-96\,{x}^{2}{c}^{2}{d}^{2}{e}^{2}+60\,ab{e}^{4}x-240\,xacd{e}^{3}-120\,{b}^{2}d{e}^{3}x+480\,bc{d}^{2}{e}^{2}x-384\,x{c}^{2}{d}^{3}e+10\,{a}^{2}{e}^{4}+40\,abd{e}^{3}-160\,ac{d}^{2}{e}^{2}-80\,{b}^{2}{d}^{2}{e}^{2}+320\,bc{d}^{3}e-256\,{c}^{2}{d}^{4}}{15\,{e}^{5}} \left ( ex+d \right ) ^{-{\frac{3}{2}}}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  int((c*x^2+b*x+a)^2/(e*x+d)^(5/2),x)

[Out]

-2/15/(e*x+d)^(3/2)*(-3*c^2*e^4*x^4-10*b*c*e^4*x^3+8*c^2*d*e^3*x^3-30*a*c*e^4*x^
2-15*b^2*e^4*x^2+60*b*c*d*e^3*x^2-48*c^2*d^2*e^2*x^2+30*a*b*e^4*x-120*a*c*d*e^3*
x-60*b^2*d*e^3*x+240*b*c*d^2*e^2*x-192*c^2*d^3*e*x+5*a^2*e^4+20*a*b*d*e^3-80*a*c
*d^2*e^2-40*b^2*d^2*e^2+160*b*c*d^3*e-128*c^2*d^4)/e^5

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Maxima [A]  time = 0.702131, size = 246, normalized size = 1.52 \[ \frac{2 \,{\left (\frac{3 \,{\left (e x + d\right )}^{\frac{5}{2}} c^{2} - 10 \,{\left (2 \, c^{2} d - b c e\right )}{\left (e x + d\right )}^{\frac{3}{2}} + 15 \,{\left (6 \, c^{2} d^{2} - 6 \, b c d e +{\left (b^{2} + 2 \, a c\right )} e^{2}\right )} \sqrt{e x + d}}{e^{4}} - \frac{5 \,{\left (c^{2} d^{4} - 2 \, b c d^{3} e - 2 \, a b d e^{3} + a^{2} e^{4} +{\left (b^{2} + 2 \, a c\right )} d^{2} e^{2} - 6 \,{\left (2 \, c^{2} d^{3} - 3 \, b c d^{2} e - a b e^{3} +{\left (b^{2} + 2 \, a c\right )} d e^{2}\right )}{\left (e x + d\right )}\right )}}{{\left (e x + d\right )}^{\frac{3}{2}} e^{4}}\right )}}{15 \, e} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate((c*x^2 + b*x + a)^2/(e*x + d)^(5/2),x, algorithm="maxima")

[Out]

2/15*((3*(e*x + d)^(5/2)*c^2 - 10*(2*c^2*d - b*c*e)*(e*x + d)^(3/2) + 15*(6*c^2*
d^2 - 6*b*c*d*e + (b^2 + 2*a*c)*e^2)*sqrt(e*x + d))/e^4 - 5*(c^2*d^4 - 2*b*c*d^3
*e - 2*a*b*d*e^3 + a^2*e^4 + (b^2 + 2*a*c)*d^2*e^2 - 6*(2*c^2*d^3 - 3*b*c*d^2*e
- a*b*e^3 + (b^2 + 2*a*c)*d*e^2)*(e*x + d))/((e*x + d)^(3/2)*e^4))/e

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Fricas [A]  time = 0.209643, size = 251, normalized size = 1.55 \[ \frac{2 \,{\left (3 \, c^{2} e^{4} x^{4} + 128 \, c^{2} d^{4} - 160 \, b c d^{3} e - 20 \, a b d e^{3} - 5 \, a^{2} e^{4} + 40 \,{\left (b^{2} + 2 \, a c\right )} d^{2} e^{2} - 2 \,{\left (4 \, c^{2} d e^{3} - 5 \, b c e^{4}\right )} x^{3} + 3 \,{\left (16 \, c^{2} d^{2} e^{2} - 20 \, b c d e^{3} + 5 \,{\left (b^{2} + 2 \, a c\right )} e^{4}\right )} x^{2} + 6 \,{\left (32 \, c^{2} d^{3} e - 40 \, b c d^{2} e^{2} - 5 \, a b e^{4} + 10 \,{\left (b^{2} + 2 \, a c\right )} d e^{3}\right )} x\right )}}{15 \,{\left (e^{6} x + d e^{5}\right )} \sqrt{e x + d}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate((c*x^2 + b*x + a)^2/(e*x + d)^(5/2),x, algorithm="fricas")

[Out]

2/15*(3*c^2*e^4*x^4 + 128*c^2*d^4 - 160*b*c*d^3*e - 20*a*b*d*e^3 - 5*a^2*e^4 + 4
0*(b^2 + 2*a*c)*d^2*e^2 - 2*(4*c^2*d*e^3 - 5*b*c*e^4)*x^3 + 3*(16*c^2*d^2*e^2 -
20*b*c*d*e^3 + 5*(b^2 + 2*a*c)*e^4)*x^2 + 6*(32*c^2*d^3*e - 40*b*c*d^2*e^2 - 5*a
*b*e^4 + 10*(b^2 + 2*a*c)*d*e^3)*x)/((e^6*x + d*e^5)*sqrt(e*x + d))

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Sympy [F]  time = 0., size = 0, normalized size = 0. \[ \int \frac{\left (a + b x + c x^{2}\right )^{2}}{\left (d + e x\right )^{\frac{5}{2}}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate((c*x**2+b*x+a)**2/(e*x+d)**(5/2),x)

[Out]

Integral((a + b*x + c*x**2)**2/(d + e*x)**(5/2), x)

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GIAC/XCAS [A]  time = 0.208683, size = 329, normalized size = 2.03 \[ \frac{2}{15} \,{\left (3 \,{\left (x e + d\right )}^{\frac{5}{2}} c^{2} e^{20} - 20 \,{\left (x e + d\right )}^{\frac{3}{2}} c^{2} d e^{20} + 90 \, \sqrt{x e + d} c^{2} d^{2} e^{20} + 10 \,{\left (x e + d\right )}^{\frac{3}{2}} b c e^{21} - 90 \, \sqrt{x e + d} b c d e^{21} + 15 \, \sqrt{x e + d} b^{2} e^{22} + 30 \, \sqrt{x e + d} a c e^{22}\right )} e^{\left (-25\right )} + \frac{2 \,{\left (12 \,{\left (x e + d\right )} c^{2} d^{3} - c^{2} d^{4} - 18 \,{\left (x e + d\right )} b c d^{2} e + 2 \, b c d^{3} e + 6 \,{\left (x e + d\right )} b^{2} d e^{2} + 12 \,{\left (x e + d\right )} a c d e^{2} - b^{2} d^{2} e^{2} - 2 \, a c d^{2} e^{2} - 6 \,{\left (x e + d\right )} a b e^{3} + 2 \, a b d e^{3} - a^{2} e^{4}\right )} e^{\left (-5\right )}}{3 \,{\left (x e + d\right )}^{\frac{3}{2}}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate((c*x^2 + b*x + a)^2/(e*x + d)^(5/2),x, algorithm="giac")

[Out]

2/15*(3*(x*e + d)^(5/2)*c^2*e^20 - 20*(x*e + d)^(3/2)*c^2*d*e^20 + 90*sqrt(x*e +
d)*c^2*d^2*e^20 + 10*(x*e + d)^(3/2)*b*c*e^21 - 90*sqrt(x*e + d)*b*c*d*e^21 + 1
5*sqrt(x*e + d)*b^2*e^22 + 30*sqrt(x*e + d)*a*c*e^22)*e^(-25) + 2/3*(12*(x*e + d
)*c^2*d^3 - c^2*d^4 - 18*(x*e + d)*b*c*d^2*e + 2*b*c*d^3*e + 6*(x*e + d)*b^2*d*e
^2 + 12*(x*e + d)*a*c*d*e^2 - b^2*d^2*e^2 - 2*a*c*d^2*e^2 - 6*(x*e + d)*a*b*e^3
+ 2*a*b*d*e^3 - a^2*e^4)*e^(-5)/(x*e + d)^(3/2)